A) \[{{80}^{o}}\]
B) \[{{50}^{o}}\]
C) \[{{40}^{o}}\]
D) \[{{160}^{o}}\]
Correct Answer: C
Solution :
In \[\Delta \,AED,\] \[\angle AED+\angle EAD+{{90}^{o}}={{180}^{o}}\](Angle sum property) \[\Rightarrow \] \[\angle AED+\angle EAD={{90}^{o}}\] \[\Rightarrow \] \[\angle EAD={{90}^{o}}-\angle AED\] ?..(i) Also, \[\angle EAD=({{50}^{o}}+\angle AFB)\] .....(ii) (Exterior angle property) From (i) and (ii), we have \[{{50}^{o}}+\angle AFB={{90}^{o}}-\angle AED\] \[\Rightarrow \] \[\angle AFB+\angle AED={{90}^{o}}-{{50}^{o}}={{40}^{o}}\] \[\Rightarrow \] \[\angle AED+\angle CFD={{40}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
