A) \[\frac{1}{x}+y\]
B) \[\frac{1}{xy}\]
C) \[\frac{1}{x}-\frac{1}{y}\]
D) \[\frac{1}{x}+\frac{1}{y}\]
Correct Answer: D
Solution :
\[\cot \,(A-B)=\frac{1}{\tan \,(A-B)}=\frac{1+\tan A\,\,\tan B}{\tan A-\tan B}\] \[=\frac{1}{\tan A-\tan B}+\frac{\tan A\,\,\tan B}{\tan A-\tan B}=\frac{1}{x}+\frac{1}{y}\].
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