A) \[\cos 2x\]
B) \[2\cos x\]
C) \[{{\cos }^{2}}x\]
D) \[1+\cos x\]
Correct Answer: B
Solution :
The given expression can be written as \[\frac{(\cos \,6x+\cos \,4x)+5\,(\cos \,4x+\cos \,2x)+10\,(\cos \,2x+1)}{\cos \,5x+5\,\cos \,3x+10\,\cos x}\] After solving, we get the required result i.e. \[2\,\cos x\].
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