A) \[\frac{2-\sqrt{3}}{2}\]
B) \[\frac{\sqrt{3}+1}{2\sqrt{2}}\]
C) \[\frac{\sqrt{3}-1}{-2\sqrt{2}}\]
D) \[\frac{\sqrt{3}-1}{2\sqrt{2}}\]
Correct Answer: B
Solution :
\[\sin \,{{75}^{o}}=\sin \,\,({{90}^{o}}-{{15}^{o}})=\cos \,{{15}^{o}}=\cos \,\,({{45}^{o}}-{{30}^{o}})\] \[=\frac{\sqrt{3}+1}{2\sqrt{2}}\].
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