A) \[{{4}^{3}}\]
B) \[{{6}^{3}}\]
C) \[{{2}^{3}}\]
D) \[{{8}^{3}}\]
Correct Answer: A
Solution :
[a] \[x\sin 45{}^\circ =y\,\text{cosec}30{}^\circ \] \[\Rightarrow \] \[\frac{x}{y}=\frac{\text{cosec}30{}^\circ }{\sin 45{}^\circ }=\frac{2}{\frac{1}{\sqrt{2}}}=2\sqrt{2}\] \[\Rightarrow \] \[\frac{{{x}^{4}}}{{{y}^{4}}}={{(2\sqrt{2})}^{4}}=64={{4}^{3}}\] |
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