SSC Quantitative Aptitude Trigonometry Question Bank Trigonometry (I)

  • question_answer
    \[(si{{n}^{4}}\theta -co{{s}^{4}}\theta +1)\,cose{{c}^{2}}\theta \]is equal to

    A) 4

    B) 3

    C) 2

    D) 1

    Correct Answer: C

    Solution :

    [c] \[\{(si{{n}^{4}}\theta -co{{s}^{4}}\theta )+1\}cose{{c}^{2}}\theta \] \[=\{(si{{n}^{2}}\theta +co{{s}^{2}}\theta )(si{{n}^{2}}\theta -co{{s}^{2}}\theta )+1\}\cdot \frac{1}{{{\sin }^{2}}\theta }\] \[=\frac{(si{{n}^{2}}\theta -co{{s}^{2}}\theta )+1}{{{\sin }^{2}}\theta }\] \[=\frac{{{\sin }^{2}}\theta +(1-co{{s}^{2}}\theta )}{{{\sin }^{2}}\theta }\] \[=\frac{2{{\sin }^{2}}\theta }{{{\sin }^{2}}}=2\]


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