A) 1
B) \[-1\]
C) 0
D) 0.5
Correct Answer: C
Solution :
[c] \[{{\sin }^{2}}\alpha +{{\sin }^{2}}\beta =2\] \[\Rightarrow \] \[\sin \alpha =\sin \beta =1\]\[(\therefore sin\theta \le 1)\] \[\Rightarrow \] \[\alpha =\beta =90{}^\circ \] \[\therefore \] \[\cos \left( \frac{\alpha +\beta }{2} \right)=\cos 90{}^\circ =0\] |
You need to login to perform this action.
You will be redirected in
3 sec