A) 3 m
B) 4 m
C) 5 m
D) 6 m
Correct Answer: C
Solution :
[c] Let the required length of shadow is x m. In \[\Delta \Alpha \Beta C,\]\[\tan 60{}^\circ =\frac{AB}{BC}\] \[\Rightarrow \] \[AB=x\sqrt{3}\] (i) In \[\Delta \Alpha BD,\]\[\tan 30{}^\circ =\frac{AB}{15}\] \[\Rightarrow \] \[\frac{1}{\sqrt{3}}=\frac{AB}{15}\] \[\therefore \] \[AB=\frac{15}{\sqrt{3}}\] (ii) From Eqs. (i) and (ii), we get \[x\sqrt{3}=\frac{15}{\sqrt{3}}\] \[\Rightarrow \] \[x=5\,m\] |
You need to login to perform this action.
You will be redirected in
3 sec