A) 80 m
B) 100 m
C) 160 m
D) 200 m
Correct Answer: A
Solution :
[a] From\[\Delta \,\Alpha \Beta C,\]\[\tan 2\theta =\frac{h}{(160-100)}\] \[\frac{2\tan \theta }{1-{{\tan }^{2}}\theta }=\frac{h}{60}\]
(i) ![]() |
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