SSC Quantitative Aptitude Trigonometry Question Bank Trigonometry (II)

  • question_answer
    If \[5\tan \,\theta =4,\]then the value of \[\left( \frac{5\sin \theta -3\cos \theta }{5\sin \theta +3\cos \theta } \right)\]is

    A) \[\frac{1}{7}\]

    B) \[\frac{2}{7}\]

    C) \[\frac{5}{7}\]

    D) \[\frac{2}{5}\]

    Correct Answer: A

    Solution :

    [a] \[\frac{5\sin \theta -3\cos \theta }{5\sin \theta +3\cos \theta }=\frac{\cos \theta \left( \frac{5\sin \theta }{\cos \theta }-3 \right)}{\cos \theta \left( 5\frac{\sin \theta }{\cos \theta }+3 \right)}\] \[=\frac{5\sin \theta -3}{5\tan \theta +3}=\frac{5\cdot \frac{4}{5}-3}{5\cdot \frac{4}{5}+3}\]                   \[(\therefore 5tan\theta =4)\] \[=\frac{1}{7}\]


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