A) \[1\]
B) \[\sqrt{2}\]
C) \[\frac{1}{\sqrt{2}}\]
D) \[0\]
Correct Answer: A
Solution :
[a] f \[(\theta )=si{{n}^{8}}\theta +{{\cos }^{14}}\theta \] \[={{\sin }^{8}}\theta +{{(1-si{{n}^{2}}\theta )}^{7}}\] \[\therefore \] \[f\,(90{}^\circ )=1+{{(1+1)}^{7}}\] [\[\because \]Maximum value of\[si{{n}^{2}}\theta =1\]] \[=1+0=1\] |
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