A) \[50\,m\]
B) \[75\sqrt{3}\,m\]
C) \[25\sqrt{3}\,m\]
D) \[80\,m\]
Correct Answer: B
Solution :
[b] Suppose the height of the kite from the ground \[=h\,m\] \[\therefore \] \[\sin 60{}^\circ =\frac{AB}{150}\] \[\Rightarrow \] \[\frac{\sqrt{3}}{2}=\frac{AB}{150}\]\[\Rightarrow \]\[\frac{\sqrt{3}}{2}=\frac{h}{150}\] \[\Rightarrow \] \[h=75\sqrt{3}\,m\] |
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