question_answer

The angle of elevation of the top of a tower at a distance of\[\frac{50\sqrt{3}}{3}\] metres from the foot is \[60{}^\circ \]. Find the height of the tower.

A)  \[50\sqrt{3}\]metres                    

B)  \[\frac{20}{\sqrt{3}}\] metres

C)  \[-50\]metres     

D)         50 metres  

Correct Answer: D

Solution :

 Let the height of the tower be h meters \[\therefore \]  \[\frac{h}{\frac{50\sqrt{3}}{3}}=\tan {{60}^{o}}\] or            \[h=50\] meters