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10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    \[\frac{{{\sec }^{2}}\theta -1}{{{\tan }^{2}}\theta }=?\]

    A)  1        

    B)  2

    C)  3                                

    D)  5

    Correct Answer: A

    Solution :

    (a): \[\frac{\sec \theta -1}{{{\tan }^{2}}\theta }=\frac{{{\tan }^{2}}\theta }{{{\tan }^{2}}\theta }=1\]             


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