A) 45
B) 30
C) 50
D) 80
Correct Answer: A
Solution :
In \[\Delta 's\] ABC and ABD, \[\angle A\] is common and \[\angle ABC=\angle ADB\] Hence \[\Delta \,ABC\] and \[\Delta \,ABD\] are equiangular \[\therefore \] \[\frac{AD}{AB}=\frac{AB}{AC}\] or \[AD=\frac{A{{B}^{2}}}{AC}=\frac{A{{C}^{2}}-B{{C}^{2}}}{AC}\]You need to login to perform this action.
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