A) \[1\]
B) \[0\]
C) \[\tan A\,\,\tan B\,\,\tan C\]
D) \[-1\]
Correct Answer: C
Solution :
Since A, B and C are the angles of a triangle \[\therefore \] \[A+B+C=\pi \] \[\therefore \] \[\tan (A+B+C)=\tan \pi =0\] or \[\frac{\tan A+\tan B+\tan C-\tan A\tan B\tan C}{1-\tan A\tan B-\tan B\tan C-\tan C\tan A}=0\] or \[\tan A+\tan B+\tan C=\tan A.\,\tan \,B.\,tanC\]You need to login to perform this action.
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