A) 1
B) ? 1
C) \[\frac{1}{2}\]
D) \[\frac{-1}{2}\]
Correct Answer: C
Solution :
(c): \[1+2{{\sin }^{2}}\theta {{\cos }^{2}}\theta =1+4k{{\sin }^{2}}\theta {{\cos }^{2}}\theta \] \[\Rightarrow \] \[0={{\sin }^{2}}\theta {{\cos }^{2}}\theta (4k-2)\] \[\Rightarrow \] \[0=4K-2\] \[\Rightarrow \] \[K=\frac{1}{2}\]You need to login to perform this action.
You will be redirected in
3 sec