A) \[50\sqrt{3}\]metres
B) \[\frac{20}{\sqrt{3}}\] metres
C) \[-50\]metres
D) 50 metres
Correct Answer: D
Solution :
Let the height of the tower be h meters \[\therefore \] \[\frac{h}{\frac{50\sqrt{3}}{3}}=\tan {{60}^{o}}\] or \[h=50\] metersYou need to login to perform this action.
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