A) 10
B) 15
C) 20
D) 22
Correct Answer: B
Solution :
Since \[\angle OQT={{45}^{o}}\] therefore \[OT=OQ=h\,(say)\] From \[\Delta OPT,\,\frac{OP}{OT}=\cot \,{{30}^{o}}\] or \[\frac{h+11}{h}=\sqrt{3}\] or \[h=\frac{11}{\sqrt{3}-1}=\frac{11}{2}(\sqrt{3}+1)\] or \[h=1.366\times 11\] \[=15.026=15\]You need to login to perform this action.
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