A) \[\frac{\sqrt{3}}{2}\]
B) \[\sqrt{3}+1\]
C) \[\sqrt{3}-1\]
D) \[\frac{2}{\sqrt{3}}\]
Correct Answer: A
Solution :
Let height of the balloon is h, and the man is first at A and after moving 1 km, he is at B. In \[\Delta \,ABC,\angle ACB={{30}^{o}}\] and \[\angle BAC={{30}^{o}}\] \[\therefore \] s\[BC=AB=1\,km\] In \[\Delta \,BOC,\] \[h=BC\,\sin \,{{60}^{o}}=\frac{\sqrt{3}}{2}\]You need to login to perform this action.
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