A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{4}{3}\]
D) \[\frac{5}{3}\]
Correct Answer: D
Solution :
\[A{{B}^{2}}=A{{C}^{2}}-B{{C}^{2}}=225\] \[\therefore \] \[AB=15\] \[\Rightarrow \] \[\tan \theta =\frac{8}{15}\] and \[\sec \theta =\frac{17}{15}\] \[\Rightarrow \] \[\tan \theta +\sec \theta =\frac{5}{3}\]You need to login to perform this action.
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