A) 0.6293
B) 0.6307
C) 0.6361
D) 0.6414
Correct Answer: C
Solution :
Given, \[\cos \,{{50}^{o}}18'=0.6388\] and \[\cos \,{{50}^{o}}42'=0.6384\] \[\therefore \] Difference for \[24'=0.0054\] \[\therefore \]Difference for \[2'=\frac{0.0054}{24}=0.00048\] Hence \[\cos \,{{50}^{o}}20'=0.6388-0.0005=0.6383\]You need to login to perform this action.
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