A) \[\left[ \begin{matrix} 8 & -5 \\ -5 & 3 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 8 & -5 \\ 5 & 3 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} 8 & -5 \\ -5 & -3 \\ \end{matrix} \right]\]
D) \[\left[ \begin{matrix} 8 & 5 \\ -5 & 3 \\ \end{matrix} \right]\]
Correct Answer: D
Solution :
\[A=\left[ \begin{matrix} 3 & 1 \\ -1 & 2 \\ \end{matrix} \right]\] \[{{A}^{2}}=A.A=\left[ \begin{matrix} 3 & 1 \\ -1 & 2 \\ \end{matrix} \right]\,\left[ \begin{matrix} 3 & 1 \\ -1 & 2 \\ \end{matrix} \right]\] \[{{A}^{2}}=\left[ \begin{matrix} 8 & 5 \\ -5 & 3 \\ \end{matrix} \right]\].You need to login to perform this action.
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