A) 20 m, 30m, 30m
B) 30 m, 40 m, 40m
C) 20m, 40m, 32m
D) 30 m, 40 m, 50m
Correct Answer: A
Solution :
Let ABCD be the theatre in which AB = AD = 20 m and let SC = CD = x m Perimeter of the theatre =100 m \[\Rightarrow 100=AB+BC+CD+DA\] \[100=(20+x+x+20)m\] \[\Rightarrow 40+2x=100\Rightarrow (20+x)=50\] \[\Rightarrow x=30m\] So, AB = AD = 20 m and BC = CD = 30 mYou need to login to perform this action.
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