A) 10
B) 8
C) 9
D) 13
Correct Answer: B
Solution :
Let n be the number of sides of the polygon. Then, Each exterior angle\[\text{=}{{\left( \frac{\text{360}}{n} \right)}^{\text{o}}}\] And each interior angle\[={{\left( \frac{2n-4}{n}\times 90 \right)}^{\text{o}}}\] According to question, we have Exterior angle \[=\frac{1}{3}\] (Inferior angle) \[\Rightarrow {{\left( \frac{360}{n} \right)}^{o}}=\frac{1}{3}{{\left( \frac{2n-4}{n}\times 90 \right)}^{o}}\] \[\Rightarrow 2n-4=12\Rightarrow 2n16\Rightarrow n=8\]
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