A) \[{{45}^{o}}\]
B) \[{{135}^{o}}\]
C) \[{{255}^{o}}\]
D) \[{{225}^{o}}\]
Correct Answer: C
Solution :
Since \[\Delta \,ABC\]is equilateral, \[\angle CBA={{60}^{o}}\] BE is the diagonal of square ABDE \[\Rightarrow \] \[\angle ABE=\frac{{{90}^{o}}}{2}={{45}^{o}}\] Therefore, the angle marked \[x\] in the figure is \[{{360}^{o}}-({{60}^{o}}+{{45}^{o}})\] \[={{360}^{o}}-{{105}^{o}}={{255}^{o}}\]You need to login to perform this action.
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