JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    The acceleration of a train travelling with speed of 400 m/s as it goes round a curve of radius 160 m, is [Pb. PET 2003]

    A)             \[1\,\,km/{{s}^{2}}\]

    B)                    \[100\,\,\,m/{{s}^{2}}\]

    C)                 \[10\,\,m/{{s}^{2}}\]

    D)                             \[1\,\,m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

        \[a=\frac{{{v}^{2}}}{r}=\frac{{{(400)}^{2}}}{160}={{10}^{3}}\,m/{{s}^{2}}=1\,km/{{s}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner