JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    A mass is supported on a frictionless horizontal surface. It is attached to a string and rotates about a fixed centre at an angular velocity \[{{\omega }_{0}}\]. If the length of the string and angular velocity are doubled, the tension in the string which was initially \[{{T}_{0}}\] is now                                     [AIIMS 1985]

    A)             \[{{T}_{0}}\]

    B)             \[{{T}_{0}}/2\]

    C)             \[4{{T}_{0}}\]          

    D)             \[8{{T}_{0}}\]

    Correct Answer: D

    Solution :

                    Tension in the string \[{{T}_{0}}=mR\omega _{0}^{2}\]             In the second case\[T=m(2R)(4\omega _{0}^{2})=8mR\omega _{0}^{2}\]\[=8{{T}_{0}}\]


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