A) \[\frac{{{\pi }^{2}}}{4}m{{s}^{-2}}\] and direction along the radius towards the centre
B) \[{{\pi }^{2}}m{{s}^{-2}}\] and direction along the radius away from the centre
C) \[{{\pi }^{2}}m{{s}^{-2}}\] and direction along the radius towards the centre
D) \[{{\pi }^{2}}m{{s}^{-2}}\] and direction along the tangent to the circle
Correct Answer: C
Solution :
a \[=\frac{{{v}^{2}}}{r}={{\omega }^{2}}r\]\[=4{{\pi }^{2}}{{n}^{2}}r=4{{\pi }^{2}}{{\left( \frac{22}{44} \right)}^{2}}\times 1\]\[={{\pi }^{2}}\,m/{{s}^{2}}\]and its direction is always along the radius and towards the centre.
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