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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    If the overbridge is concave instead of being convex, the thrust on the road at the lowest position will be

    A)             \[mg+\frac{m{{v}^{2}}}{r}\]

    B)            \[mg-\frac{m{{v}^{2}}}{r}\]

    C)             \[\frac{{{m}^{2}}{{v}^{2}}g}{r}\]

    D)                      \[\frac{{{v}^{2}}g}{r}\]

    Correct Answer: A

    Solution :

                    Thrust at the lowest point of concave bridge             = \[mg+\frac{m{{v}^{2}}}{r}\]


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