A) 1 : 12
B) 6 : 1
C) 12 : 1
D) 1 : 6
Correct Answer: C
Solution :
\[{{\omega }_{\min }}=\frac{2\pi }{60}\ \frac{Rad}{min}\]and \[{{\omega }_{hr}}=\frac{2\pi }{12\times 60}\ \frac{Rad}{min}\] \ \[\frac{{{\omega }_{\min }}}{{{\omega }_{hr}}}=\frac{2\pi /60}{2\pi /12\times 60}\]
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