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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    A motor cyclist moving with a velocity of 72 km/hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 meters. The acceleration due to gravity is 10 m/sec2. In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than                            [CPMT 1986]

    A)             \[\theta ={{\tan }^{-1}}6\]

    B)                      \[\theta ={{\tan }^{-1}}2\]

    C)             \[\theta ={{\tan }^{-1}}25.92\]

    D)                      \[\theta ={{\tan }^{-1}}4\]

    Correct Answer: B

    Solution :

                    \[v=72\,km/hour=20\,m/\sec \]                       \[\theta ={{\tan }^{-1}}\left( \frac{{{v}^{2}}}{rg} \right)={{\tan }^{-1}}\left( \frac{20\times 20}{20\times 10} \right)={{\tan }^{-1}}(2)\]


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