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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    A particle moves in a circle of radius 25 cm at two revolutions per second. The acceleration of the particle in \[m/{{s}^{2}}\] is     [MNR 1991; UPSEAT 2000;                                     DPMT 1999; RPET 2003; Pb. PET 2004]

    A)             \[{{\pi }^{2}}\]        

    B)             \[8{{\pi }^{2}}\]

    C)             \[4{{\pi }^{2}}\]      

    D)             \[2{{\pi }^{2}}\]

    Correct Answer: C

    Solution :

                    Since \[n=2\], \[\omega =2\pi \times 2=4\pi \,rad/{{s}^{2}}\] So acceleration \[={{\omega }^{2}}r\]\[={{(4\pi )}^{2}}\times \frac{25}{100}\,m/{{s}^{2}}=4{{\pi }^{2}}\]


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