A) 20 \[m{{s}^{-1}}\]
B) 16 \[m{{s}^{-1}}\]
C) 14 \[m{{s}^{-1}}\]
D) 12 \[m{{s}^{-1}}\]
Correct Answer: D
Solution :
Maximum tension = \[\frac{m{{v}^{2}}}{r}=16N\] Þ\[\frac{16\times {{v}^{2}}}{144}=16\]Þ v = 12 m/sYou need to login to perform this action.
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