JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/hr. The centripetal force is                         [KCET 2001; CBSE PMT 1999; JIPMER 2001, 02]

    A)             250 N

    B)                      750 N

    C)             1000 N

    D)                      1200 N

    Correct Answer: C

    Solution :

                    \[v=36\frac{km}{h}=10\frac{m}{s}\]\ \[F=\frac{m{{v}^{2}}}{r}=\frac{500\times 100}{50}=1000N.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner