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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal circle. The maximum tension the string can withstand is 16 Newton. The maximum velocity of revolution that can be given to the stone without breaking it, will be                               [SCRA 1994]

    A)             20 \[m{{s}^{-1}}\]

    B)                      16 \[m{{s}^{-1}}\]

    C)             14 \[m{{s}^{-1}}\]

    D)                      12 \[m{{s}^{-1}}\]

    Correct Answer: D

    Solution :

                    Maximum tension = \[\frac{m{{v}^{2}}}{r}=16N\]             Þ\[\frac{16\times {{v}^{2}}}{144}=16\]Þ v = 12 m/s


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