JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    The angular speed of seconds needle in a mechanical watch is [RPMT 1999; CPMT 1997; MH CET 2000, 01; BHU 2000]

    A)             \[\frac{\pi }{30}\]rad/s

    B)                      \[2\pi \]rad/s

    C)             \[\pi \]rad/s

    D)                      \[\frac{60}{\pi }\]rad/s

    Correct Answer: A

    Solution :

                    \[\omega =\frac{2\pi }{T}=\frac{2\pi }{60}=\frac{\pi }{30}\,rad/s\]


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