A) \[\frac{{{v}^{2}}b}{Rg}\]
B) \[\frac{v}{Rgb}\]
C) \[\frac{{{v}^{2}}R}{g}\]
D) \[\frac{{{v}^{2}}b}{R}\]
Correct Answer: A
Solution :
We know that \[\tan \theta =\frac{{{v}^{2}}}{Rg}\] and \[\tan \theta =\frac{h}{b}\] Hence \[\frac{h}{b}=\frac{{{v}^{2}}}{Rg}\] Þ \[h=\frac{{{v}^{2}}b}{Rg}\]You need to login to perform this action.
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