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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    If a particle covers half the circle of radius R with constant speed then                                    [RPMT 2000]

    A)             Momentum change is mvr

    B)                         Change in K.E. is 1/2 mv2            

    C)             Change in K.E. is mv2

    D)             Change in K.E. is zero

    Correct Answer: D

    Solution :

                    As momentum is vector quantity \ change in momentum \[\Delta P\]= \[2mv\sin (\theta /2)\] =\[2mv\sin (90)=2mv\] But kinetic energy remains always constant so change in kinetic energy is zero.


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