A) 5 r.p.m.
B) 10 r.p.m.
C) 20 r.p.m.
D) 14 r.p.m.
Correct Answer: A
Solution :
\[T=m{{\omega }^{2}}r\]Þ \[\omega \propto \sqrt{T}\]\\[\frac{{{\omega }_{2}}}{{{\omega }_{1}}}=\sqrt{\frac{1}{4}}\Rightarrow {{\omega }_{2}}=\frac{{{\omega }_{1}}}{2}=5\,rpm\]
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