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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    If a cycle wheel of radius 4 m completes one revolution in two seconds.  Then acceleration of a point on the cycle wheel will be                            [Pb. PMT 2001]

    A)             \[{{\pi }^{2}}m/{{s}^{2}}\]

    B)                      \[2{{\pi }^{2}}m/{{s}^{2}}\]

    C)             \[4{{\pi }^{2}}m/{{s}^{2}}\]

    D)                      \[8\pi \,m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

                    Centripetal acceleration\[=4{{\pi }^{2}}{{n}^{2}}r=4{{\pi }^{2}}{{\left( \frac{1}{2} \right)}^{2}}\times 4=4{{\pi }^{2}}\]


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