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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    A proton of mass 1.6 × 10?27 kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4 × 10?13 N.  then the frequency of revolution of the proton is about                                     [Kerala (Med.) 2002]

    A)             0.08 × 108 cycles per sec       

    B)             4 × 108 cycles per sec

    C)             8 × 108 cycles per sec

    D)             12 × 108 cycles per sec

    Correct Answer: A

    Solution :

                    \[m\,4{{\pi }^{2}}{{n}^{2}}r=4\times {{10}^{-13}}\]Þ \[n=0.08\times {{10}^{8}}\,cycles/\sec .\]


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