question_answer

Let\[[{{\in }_{0}}]\]denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:

A) \[{{\in }_{0}}=[{{M}^{-1}}{{L}^{-3}}{{T}^{2}}A]\]      

B) \[{{\in }_{0}}=[{{M}^{1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}}]\]

C) \[{{\in }_{0}}=[{{M}^{1}}{{L}^{2}}{{T}^{1}}{{A}^{2}}]\]    

D) \[{{\in }_{0}}=[{{M}^{1}}{{L}^{2}}{{T}^{1}}A]\]