Answer:
Unit of length \[=\] unit of velocity \[\times \] unit of time \[=3\times {{10}^{8}}m{{s}^{-1}}\times 1year\] \[=3\times {{10}^{8}}m{{s}^{-1}}\times 365\times 24\times 60\times 60s\] \[=9.45\times {{10}^{15}}m{{s}^{-1}}\] \[=1\,\text{light year}\]
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