JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Units

  • question_answer
    A suitable unit for gravitational constant is [MNR 1988]

    A) \[kg\text{-}\,m{{\sec }^{-1}}\]

    B) \[N\ {{m}^{-1}}\sec \]

    C) \[N\,\,{{m}^{2}}\,k{{g}^{-2}}\]

    D) \[kg\,m\,{{\sec }^{-1}}\]

    Correct Answer: C

    Solution :

    \[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{d}^{2}}};\] \[\therefore \] \[G=\frac{F{{d}^{2}}}{{{m}_{1}}{{m}_{2}}}=N{{m}^{2}}/k{{g}^{2}}\]


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