A) 1
B) 10
C) 0.1
D) 0.01
Correct Answer: C
Solution :
\[Y=\frac{F}{A}.\frac{L}{\Delta L}\]= \[\frac{dyne}{c{{m}^{2}}}=\frac{{{10}^{-5}}N}{{{10}^{-4}}{{m}^{2}}}=0.1N/{{m}^{2}}\]You need to login to perform this action.
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