A) \[\frac{2}{n}\]
B) \[\frac{1}{n}\]
C) \[\frac{2}{(n-1)\,!}\]
D) None of these
Correct Answer: A
Solution :
Total number of ways \[=n\,\,!\]. Favourable cases \[=2(n-1)\,\,!\] Hence required probability \[=\frac{2(n-1)\,\,!}{n\,\,!}=\frac{2}{n}\].You need to login to perform this action.
You will be redirected in
3 sec