A) \[\frac{3}{5}\]
B) \[\frac{2}{5}\]
C) \[\frac{4}{5}\]
D) \[\frac{1}{5}\]
Correct Answer: C
Solution :
Total number of ways \[=\frac{10\,!}{2\,!}\] Favourable number of ways for \['I'\] come together is \[9\,!\] Thus probability that \['I'\] come together \[=\frac{9\,!\,\times \,2\,!}{10\,!}=\frac{2}{10}=\frac{1}{5}\]. Hence required probability \[=1-\frac{1}{5}=\frac{4}{5}.\]
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