A) \[\frac{5}{1296}\]
B) \[\frac{5}{1944}\]
C) \[\frac{5}{2592}\]
D) None of these
Correct Answer: C
Solution :
\[n=\]Total number of ways \[={{6}^{5}}\] \[A\] total of 12 in 5 throw can be obtained in following two ways ? (i) One blank and four \[3's={}^{5}{{C}_{1}}=5\] or (ii) Three \[2's\] and two \[3's={}^{5}{{C}_{2}}=10\] Hence, the required probability \[=\frac{15}{{{6}^{5}}}=\frac{5}{2592}.\]
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