JEE Main & Advanced Mathematics Probability Question Bank Use of permutations and combinations in probability

  • question_answer
    A bag has 13 red, 14 green and 15 black balls. The probability of getting exactly 2 blacks on pulling out 4 balls is \[{{P}_{1}}.\]Now the number of each colour ball is doubled and 8 balls are pulled out. The probability of getting exactly 4 blacks is  \[{{P}_{2}}.\] Then

    A)            \[{{P}_{1}}={{P}_{2}}\]     

    B)            \[{{P}_{1}}>{{P}_{2}}\]

    C)            \[{{P}_{1}}<{{P}_{2}}\]     

    D)            None of these

    Correct Answer: B

    Solution :

                       \[{{P}_{1}}=\frac{{}^{15}{{C}_{2}}\times {}^{27}{{C}_{2}}}{{}^{42}{{C}_{4}}}=\frac{27}{82}\]                    and \[{{P}_{2}}=\frac{{}^{30}{{C}_{4}}\times {}^{54}{{C}_{4}}}{{}^{84}{{C}_{8}}}=\frac{17\,.\,29\,.\,45\,.\,53}{11\,.\,79\,.\,82\,.\,83}\]                                                                               (After simplification)                    Hence \[{{P}_{1}}>{{P}_{2}}.\]


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